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Dedekind 0.0.0
A structuralist C++23 Module Library
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HasSubset plus a bool ==, so \(A \subsetneq B \equiv A
\subseteq B \wedge A \neq B\) is expressible.
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HasSubset plus a bool ==, so \(A \subsetneq B \equiv A
\subseteq B \wedge A \neq B\) is expressible.